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演示从注册表中还原MSNMessenger口令

杀毒教程2024-04-21 阅读
网络技术是从1990年代中期发展起来的新技术,它把互联网上分散的资源融为有机整体,实现资源的全面共享和有机协作,使人们能够透明地使用资源的整体能力并按需获取信息。资源包括高性能计算机、存储资源、数据资源、信息资源、知识资源、专家资源、大型数据库、网络、传感器等。 当前的互联网只限于信息共享,网络则被认为是互联网发展的第三阶段。

tombkeeper (t0mbkeeper_at_hotmail.com) /* MSNMessenger的口令是经过DPAPI加密后保存在注册表中的
* 这个程序演示解码过程
* tombkeeper[0x40]nsfocus[0x2e]com
* tombkeeper[0x40]xfocus[0x2e]net
* 2004.08.11
*/#include <Windows.h>
#pragma comment(lib, "Advapi32.lib")#define FCHK(a) if (!(a)) {printf(#a " failed\n"); return 0;}typedef struct _CRYPTOAPI_BLOB {
DWORD cbData;
BYTE* pbData;
} DATA_BLOB;typedef struct _CRYPTPROTECT_PROMPTSTRUCT {
DWORD cbSize;
DWORD dwPromptFlags;
HWND hwndApp;
LPCWSTR szPrompt;
} CRYPTPROTECT_PROMPTSTRUCT, *PCRYPTPROTECT_PROMPTSTRUCT;typedef BOOL (WINAPI *PCryptUnprotectData)(
DATA_BLOB* pDataIn,
LPWSTR* ppszDataDescr,
DATA_BLOB* pOptionalEntropy,
PVOID pvReserved,
CRYPTPROTECT_PROMPTSTRUCT* pPromptStruct,
DWORD dwFlags,
DATA_BLOB* pDataOut
);PCryptUnprotectData CryptUnprotectData = NULL;
int main(void)
{
int ret;
HMODULE hNtdll;HKEY hKey;
DWORD dwType;
char Data[0x100] = {0};
DWORD dwSize;DATA_BLOB DataIn;
DATA_BLOB DataOut;ret = RegOpenKeyEx
(
HKEY_CURRENT_USER,
"Software\\Microsoft\\MSNMessenger",
0,
KEY_READ,
&hKey
);
if( ret != ERROR_SUCCESS ) return 1;ret = RegQueryValueEx
(
hKey,
"Password.NET Messenger Service",
NULL,
&dwType,
Data,
&dwSize
);
if( ret != ERROR_SUCCESS ) return 1;FCHK ((hNtdll = LoadLibrary ("Crypt32.dll")) != NULL);
FCHK ((CryptUnprotectData = (PCryptUnprotectData)
GetProcAddress (hNtdll, "CryptUnprotectData")) != NULL);DataIn.pbData = Data + 2; //口令密文从第二位开始
DataIn.cbData = dwSize-2;CryptUnprotectData
(
&DataIn,
NULL,
NULL,
NULL,
NULL,
1,
&DataOut
);base64_decode (DataOut.pbData, Data, strlen(DataOut.pbData));
printf ( "MSN Password: %s\n", Data);
return 0;
}//copied from GNU libc - libc/resolv/base64.c
int base64_decode (char const *src, char *target, size_t targsize)
{
static const char Base64[] =
"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
static const char Pad64 = '=';int tarindex, state, ch;
char *pos;state = 0;
tarindex = 0;while ((ch = *src++) != '\0')
{
if (isspace (ch)) /* Skip whitespace anywhere. */
continue;if (ch == Pad64)
break;pos = strchr (Base64, ch);
if (pos == 0) /* A non-base64 character. */
return (-1);switch (state)
{
case 0:
if (target)
{
if ((size_t) tarindex >= targsize)
return (-1);
target[tarindex] = (pos - Base64) << 2;
}
state = 1;
break;
case 1:
if (target)
{
if ((size_t) tarindex + 1 >= targsize)
return (-1);
target[tarindex] (专业提供视频软件下载)

= (pos - Base64) >> 4;
target[tarindex + 1] = ((pos - Base64) & 0x0f) << 4;
}
tarindex++;
state = 2;
break;
case 2:
if (target)
{
if ((size_t) tarindex + 1 >= targsize)
return (-1);
target[tarindex] (专业提供视频软件下载)

= (pos - Base64) >> 2;
target[tarindex + 1] = ((pos - Base64) & 0x03) << 6;
}
tarindex++;
state = 3;
break;
case 3:
if (target)
{
if ((size_t) tarindex >= targsize)
return (-1);
target[tarindex] (专业提供视频软件下载)

= (pos - Base64);
}
tarindex++;
state = 0;
break;
default:
abort ();
}
}/*
* We are done decoding Base-64 chars. Let's see if we ended
* on a byte boundary, and/or with erroneous trailing characters.
*/if (ch == Pad64)
{ /* We got a pad char. */
ch = *src++; /* Skip it, get next. */
switch (state)
{
case 0: /* Invalid = in first position */
case 1: /* Invalid = in second position */
return (-1);case 2: /* Valid, means one byte of info */
/* Skip any number of spaces. */
for ((void) NULL; ch != '\0'; ch = *src++)
if (!isspace (ch))
break;
/* Make sure there is another trailing = sign. */
if (ch != Pad64)
return (-1);
ch = *src++; /* Skip the = */
/* Fall through to "single trailing =" case. */
/* FALLTHROUGH */case 3: /* Valid, means two bytes of info */
/*
* We know this char is an =. Is there anything but
* whitespace after it?
*/
for ((void) NULL; ch != '\0'; ch = *src++)
if (!isspace (ch))
return (-1);/*
* Now make sure for cases 2 and 3 that the "extra"
* bits that slopped past the last full byte were
* zeros. If we don't check them, they become a
* subliminal channel.
*/
if (target && target[tarindex] != 0)
return (-1);
}
}
else
{
/*
* We ended by seeing the end of the string. Make sure we
* have no partial bytes lying around.
*/
if (state != 0)
return (-1);
}return (tarindex);
}
网络的神奇作用吸引着越来越多的用户加入其中,正因如此,网络的承受能力也面临着越来越严峻的考验―从硬件上、软件上、所用标准上......,各项技术都需要适时应势,对应发展,这正是网络迅速走向进步的催化剂。



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